下面的程序是在3.5下的!!孔的位置度从得到的结果看。应该是孔的评价长度是孔的Z坐标到给定高度之间长度上质心的坐标。因为理论长度和实际测量的长度区别,所以不能用理论上的两个平面去截取这个长度,因为斜孔的延伸方向直接影响斜孔质心的位置,理论上的平面和实际测量的实际上的起点和终点平面有一个小小的差别,就这个孔来说,大概对位置度有0.013的区别!用实际测量平面截取两端得到的质心和位置度完全一致!至于3.7我想从这个根本上应该没有区别的。 注意下面程序中两点的Z值。
CY1 =AUTO/CYLINDER, SHOWALLPARAMS=YES, SHOWHITS=YES
THEO/0,0,20,0,0,1,40,10
ACTL/-1.925,0,20,-0.1713945,-0.0000038,0.9852025,39.969,10
TARG/0,0,20,0,0,1
THEO_THICKNESS = 0, RECT, IN, STRAIGHT, LEAST_SQR, ONERROR = NO ,$
AUTO MOVE = NO, DISTANCE = 0, RMEAS = None, READ POS = NO, FIND HOLE = NO, REMEASURE = NO, USE THEO = NO ,$
NUMHITS = 4, NUMROWS = 4, INIT = 0, PERM = 0, SPACER = 0, PITCH = 0 ,$
START ANG = 0, END ANG = 360, DEPTH = 5 ,$
ANGLE VEC = 1,0,0
MEAS/CYLINDER
HIT/BASIC,22,0,10,-1,0,0,22,0,5
HIT/BASIC,0,20,10,0,-1,0,0,20,5
HIT/BASIC,-20,0,10,1,0,0,-20,0,5
HIT/BASIC,0,-20,10,0,1,0,0,-20,5
HIT/BASIC,0,-20,11.667,0,1,0,0,-20,6.667
HIT/BASIC,-20,0,11.667,1,0,0,-20,0,6.667
HIT/BASIC,0,20,11.667,0,-1,0,0,20,6.667
HIT/BASIC,20,0,11.667,-1,0,0,20,0,6.667
HIT/BASIC,20,0,13.333,-1,0,0,20,0,8.333
HIT/BASIC,0,20,13.333,0,-1,0,0,20,8.333
HIT/BASIC,-20,0,13.333,1,0,0,-20,0,8.333
HIT/BASIC,0,-20,13.333,0,1,0,0,-20,8.333
HIT/BASIC,0,-20,15,0,1,0,0,-20,10
HIT/BASIC,-20,0,15,1,0,0,-20,0,10
HIT/BASIC,0,20,15,0,-1,0,0,20,10
HIT/BASIC,20,0,15,-1,0,0,20,0,10
ENDMEAS/
ASSIGN/ZD = CY1.EXYZ
ASSIGN/QD = CY1.SXYZ
ASSIGN/A = CY1.IJK
M20 =GENERIC/PLANE,DEPENDENT,RECT,$
NOM/XYZ,QD.X,QD.Y,QD.Z,$
MEAS/XYZ,QD.X,QD.Y,QD.Z,$
NOM/IJK,A.I,A.J,A.K,$
MEAS/IJK,A.I,A.J,A.K
M10 =GENERIC/PLANE,DEPENDENT,RECT,$
NOM/XYZ,ZD.X,ZD.Y,ZD.Z,$
MEAS/XYZ,ZD.X,ZD.Y,ZD.Z,$
NOM/IJK,0,0,1,$
MEAS/IJK,0,0,1
P20 =FEAT/POINT,RECT
THEO/0,0,20.334,0,0,1
ACTL/-1.925,0,20,-0.1713945,-0.0000038,0.9852025
CONSTR/POINT,PIERCE,CY1,M20
P10 =FEAT/POINT,RECT
THEO/0,0,10.148,0,0,1
ACTL/-0.211,0,10.148,-0.1713945,-0.0000038,0.9852025
CONSTR/POINT,PIERCE,CY1,M10
L20-10 =FEAT/LINE,RECT,UNBND
THEO/0,0,20.334,0,0,-1
ACTL/-1.925,0,20,0.1713945,0.0000038,-0.9852025
CONSTR/LINE,BF,3D,P20,P10,,
DIM 2= TRUE POSITION OF CYLINDER CY1 USE AXIS=AVERAGE REF LENGTH=0.000
AX NOMINAL MEAS
X 0.000 -1.068
END OF DIMENSION 2
DIM 3= LOCATION OF LINE L20-10
AX NOMINAL MEAS
X 0.000 -1.068
END OF DIMENSION 3
[此贴子已经被作者于2007-1-1 19:44:01编辑过]