社区活动 技术论坛 (求救)如何在标准球上分五层共探测25个点??
(求救)如何在标准球上分五层共探测25个点??
2007-01-22 19:40 76 0 10
为了测试三坐标的探测误差,新的国标里规定测球点数为25点!!! 我知道用自动测球功能完成,但是我要用点来测,并且球的直径大小不一,每的要均匀分布且保证I,J,K都是正确的。我要求只要不同的球输入一个直径,然后在标准球正上方打一点,它就能自动去探测25点!类似于校针程序一样!! 各位高手请指点迷津啊!!!! 先谢了。。。
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为了测试三坐标的探测误差,新的国标里规定测球点数为25点!!! 我知道用自动测球功能完成,但是我要用点来测,并且球的直径大小不一,每的要均匀分布且保证I,J,K都是正确的。我要求只要不同的球输入一个直径,然后在标准球正上方打一点,它就能自动去探测25点!类似于校针程序一样!! 各位高手请指点迷津啊!!!! 先谢了。。。
2007-01-22 19:40
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有标准的检测程序,有兴趣也可以自己做一个。 最新的国标第一层第一点不能平行于任何一轴,并且这个角度是可选的。
2007-01-22 19:46
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自己怎么做? 请指教啊
2007-01-22 20:09
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请各位大侠指教啊!!!!
2007-01-22 20:12
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[attachimg]zyj@222813317028.jpg[/attachimg] 这个是我做的程序, 脱机运行的,所以数据不对头。
2007-01-22 20:35
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[attachimg]zyj@222816837040.jpg[/attachimg] [attachimg]zyj@222816837149.jpg[/attachimg]
2007-01-22 21:34
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[quote][b]以下引用[i]zyj于2007-1-22 19:45:57[/i]的发言:[/b] 最新的国标第一层第一点不能平行于任何一轴,并且这个角度是可选的。 [/quote] ??? 不理解。。
2007-01-22 23:12
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时间仓促做的有点糙。 希望能 帮到你! =ALIGNMENT/START,RECALL:, LIST= YES ALIGNMENT/END MODE/MANUAL MOVESPEED/ 100 TOUCHSPEED/ 20 LOADPROBE/100-6X50 TIP/T1A0B0, SHANKIJK=0, 0, 1, ANGLE=0 FORMAT/TEXT,OPTIONS,HEADINGS,SYMBOLS, ;NOM,TOL,MEAS,DEV,OUTTOL, , DISPLAYPRECISION/5 ASSIGN/ID = PROBEDATA("ID") ASSIGN/CT = PROBEDATA("Vector",ID,"TESA") C1 =COMMENT/INPUT,输入球半径 F1 =GENERIC/POINT,DEPENDENT,RECT,$ NOM/XYZ,0,0,0,$ MEAS/XYZ,0,0,0,$ NOM/IJK,CT.I,CT.J,CT.K,$ MEAS/IJK,CT.I,CT.J,CT.K MODE/MANUAL D0 =AUTO/VECTOR POINT, SHOWALLPARAMS=NO THEO/0,0,0,0,0,1 ACTL/0,0,0,0,0,1 TARG/0,0,0,0,0,1 MODE/DCC A0 =ALIGNMENT/START,RECALL:, LIST= YES ALIGNMENT/LEVEL,ZPLUS,F1 ALIGNMENT/TRANS,XAXIS,D0 ALIGNMENT/TRANS,YAXIS,D0 ALIGNMENT/TRANS,ZAXIS,D0 ALIGNMENT/TRANS_OFFSET,ZAXIS,-C1.INPUT ALIGNMENT/END Q1 =AUTO/SPHERE, SHOWALLPARAMS=YES, SHOWHITS=NO THEO/0,0,0,0,0,1,C1.INPUT*2 ACTL/0,0,0,0,0,1,80 TARG/0,0,0,0,CT.J,CT.K THEO_THICKNESS = 0, RECT, OUT ,$ AUTO MOVE = NO, DISTANCE = 0 ,$ NUMHITS = 9, NUMROWS = 3, INIT = 0, PERM = 0, SPACER = 0 ,$ START ANGLE 1 = 0, END ANGLE 1 = 360 ,$ START ANGLE 2 = 0, END ANGLE 2 = 90 ,$ ANGLE VEC = 0,0,1 A1 =ALIGNMENT/START,RECALL:A0, LIST= YES ALIGNMENT/TRANS,XAXIS,Q1 ALIGNMENT/TRANS,YAXIS,Q1 ALIGNMENT/TRANS,ZAXIS,Q1 ALIGNMENT/END ASSIGN/II = 1 ASSIGN/JK = 0 ASSIGN/AA = 0 DO/ A2 =ALIGNMENT/START,RECALL:A1, LIST= YES ALIGNMENT/ROTATE_OFFSET,AA,ABOUT,ZPLUS ALIGNMENT/END D1 =AUTO/VECTOR POINT, SHOWALLPARAMS=NO THEO/C1.INPUT,JK,JK,II,JK,JK ACTL/40,0,0,1,0,0 TARG/C1.INPUT,JK,JK,II,JK,JK D2 =AUTO/VECTOR POINT, SHOWALLPARAMS=NO THEO/COS(DEG2RAD(45))*C1.INPUT,JK,SIN(DEG2RAD(45))*C1.INPUT,COS(DEG2RAD(45)),JK,SIN(DEG2RAD(45)) ACTL/28.28428,0,28.28428,0.7071068,0,0.7071068 TARG/COS(DEG2RAD(45))*C1.INPUT,JK,SIN(DEG2RAD(45))*C1.INPUT,COS(DEG2RAD(45)),JK,SIN(DEG2RAD(45)) ASSIGN/AA = AA+45 ASSIGN/II = 1 ASSIGN/JK = 0 UNTIL/AA==360 A3 =ALIGNMENT/START,RECALL:A2, LIST= YES ALIGNMENT/ROTATE_OFFSET,22.5,ABOUT,ZPLUS ALIGNMENT/END ASSIGN/BB = 0 DO/ A4 =ALIGNMENT/START,RECALL:A3, LIST= YES ALIGNMENT/ROTATE_OFFSET,BB,ABOUT,ZPLUS ALIGNMENT/END D3 =AUTO/VECTOR POINT, SHOWALLPARAMS=NO THEO/COS(DEG2RAD(22.5))*C1.INPUT,JK,SIN(DEG2RAD(22.5))*C1.INPUT,COS(DEG2RAD(22.5)),JK,SIN(DEG2RAD(22.5)) ACTL/36.95518,0,15.30734,0.9238808,0,0.3826803 TARG/COS(DEG2RAD(22.5))*C1.INPUT,JK,SIN(DEG2RAD(22.5))*C1.INPUT,COS(DEG2RAD(22.5)),JK,SIN(DEG2RAD(22.5)) ASSIGN/BB = BB+90 ASSIGN/JK = 0 UNTIL/BB==360 A5 =ALIGNMENT/START,RECALL:A4, LIST= YES ALIGNMENT/ROTATE_OFFSET,45,ABOUT,ZPLUS ALIGNMENT/END ASSIGN/CC = 0 DO/ A6 =ALIGNMENT/START,RECALL:A5, LIST= YES ALIGNMENT/ROTATE_OFFSET,CC,ABOUT,ZPLUS ALIGNMENT/END D4 =AUTO/VECTOR POINT, SHOWALLPARAMS=NO THEO/COS(DEG2RAD(67.5))*C1.INPUT,JK,SIN(DEG2RAD(67.5))*C1.INPUT,COS(DEG2RAD(67.5)),JK,SIN(DEG2RAD(67.5)) ACTL/0,-15.30734,36.95518,0,-0.3826803,0.9238808 TARG/COS(DEG2RAD(67.5))*C1.INPUT,JK,SIN(DEG2RAD(67.5))*C1.INPUT,COS(DEG2RAD(67.5)),JK,SIN(DEG2RAD(67.5)) ASSIGN/CC = CC+90 ASSIGN/JK = 0 UNTIL/CC==360 D5 =AUTO/VECTOR POINT, SHOWALLPARAMS=NO THEO/0,0,C1.INPUT,0,0,1 ACTL/0,0,40,0,0,1 TARG/0,0,C1.INPUT,0,0,1 Q2 =FEAT/SPHERE,RECT,OUT THEO/0.74066,-0.55278,-0.3326,0,0,1,80.95028 ACTL/0,0,0.00001,0,0,1,80 CONSTR/SPHERE,BF,D1[1],D1[2],D1[3],D1[4],D1[5],D1[6],D1[7],D1[8],D3[1],D3[2],D3[3],D3[4],D2[1],D2[2],D2[3],D2[4],D2[5],D2[6],D2[7],D2[8],D4[1],D4[2],D4[3],D4[4],D5,, ASSIGN/S = 1 DO/ DIM 1= 3D DISTANCE FROM POINT D1[1] TO SPHERE Q2, NO_RADIUS UNITS=MM ,$ GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH AX NOMINAL +TOL -TOL MEAS DEV OUTTOL M 40.00000 0.00000 0.00000 40.00000 0.00000 0.00000 ----#---- DIM 2= 3D DISTANCE FROM POINT D2[1] TO SPHERE Q2, NO_RADIUS UNITS=MM ,$ GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH AX NOMINAL +TOL -TOL MEAS DEV OUTTOL M 40.00000 0.00000 0.00000 40.00001 0.00001 0.00001 --------> ASSIGN/S = S+1 UNTIL/S==8 ASSIGN/S2 = 1 DO/ DIM 3= 3D DISTANCE FROM POINT D3[S2] TO SPHERE Q2, NO_RADIUS UNITS=MM ,$ GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH AX NOMINAL +TOL -TOL MEAS DEV OUTTOL M 40.00000 0.00000 0.00000 40.00000 0.00000 0.00000 ----#---- DIM 4= 3D DISTANCE FROM POINT D4[S2] TO SPHERE Q2, NO_RADIUS UNITS=MM ,$ GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH AX NOMINAL +TOL -TOL MEAS DEV OUTTOL M 40.00000 0.00000 0.00000 39.99999 -0.00001 0.00001 <-------- ASSIGN/S2 = S2+1 UNTIL/S2==4 DIM 5= 3D DISTANCE FROM POINT D5 TO SPHERE Q2, NO_RADIUS UNITS=MM ,$ GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH AX NOMINAL +TOL -TOL MEAS DEV OUTTOL M 40.00000 0.00000 0.00000 39.99999 -0.00001 0.00001 <-------- 因为角度变弧度软件计算有点BUG 所以在精度上用最大。 我用的3.5 可能别的版本应该不会这样了 另外程序可以用一个循环下面根三个判断实现,会简洁很多,时间关系就不做了,自己可以实验下。                   [此贴子已经被作者于2007-1-23 8:11:01编辑过]
2007-01-23 07:53
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版主就是牛啊,谢谢版主!!!!
2007-01-24 22:49
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惭愧!程序做的粗糙,自己用的时候再修改下吧,大概意思就是这样,另外别忘记加个安全平面,不然会撞的!十分感谢谢 周提供的 新国家标准。{/hx}{/hx}
2007-01-25 11:10
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